The effect of non-random mating on H

Given 2 cases, with N = 150 and Ne = 100 (population A)

Ne = 36 (population B)

Ht=1 = 1 - 1 Ht = the proportion of heterozygosity

2 Ne remaining in the next (t=1) generation

Population A: Ht = 1 - 1 = 1 - .005 = .995

2 x 100

Population B: Ht = 1 - 1 = 1 - .014 = .986

2 x 36

% H

remaining

after

t=1

generations

36A-1